2017年2月

准备数据

DROP TABLE IF EXISTS `score`;
CREATE TABLE `score` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(255) DEFAULT NULL,
  `score` int(11) DEFAULT NULL,
  `type` varchar(255) DEFAULT '',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;

INSERT INTO `score`
(`name`, `type`, `score`)
VALUES
('张三','语文',89),
('张三','数学',100),
('张三','英语',93),
('李四','语文',90),
('李四','数学',94),
('李四','英语',83);

score 表:

namescoretype
张三89语文
张三100数学
张三93英语
李四90语文
李四94数学
李四83英语

想要的效果:

姓名语文数学英语总分
张三89.00100.0093.00282
李四90.0094.0083.00267
平均分89.5097.0088.00-

采用 IF 语法查询

SELECT name AS '姓名',
SUM(IF(type='语文', score, 0)) AS '语文',
SUM(IF(type='数学', score, 0)) AS '数学',
SUM(IF(type='英语', score, 0)) AS '英语',
SUM(score) AS '总分'
FROM score 
GROUP BY name

UNION ALL
SELECT '平均分',
ROUND(AVG(IF(type = '语文', score, NULL)), 2) AS '语文',
ROUND(AVG(IF(type = '数学', score, NULL)), 2) AS '数学',
ROUND(AVG(IF(type = '英语', score, NULL)), 2) AS '英语',
'-' AS '总分'
FROM score

使用 CASE 语法查询

SELECT name AS '姓名',
MAX(CASE type WHEN '语文' THEN score ELSE 0 END) AS '语文',
MAX(CASE type WHEN '数学' THEN score ELSE 0 END) AS '数学',
MAX(CASE type WHEN '英语' THEN score ELSE 0 END) AS '英语',
SUM(score) AS "总分"
FROM score 
GROUP BY `name`

UNION ALL
SELECT '平均分',
ROUND(AVG(CASE type WHEN '语文' THEN score ELSE NULL END), 2) AS '语文',
ROUND(AVG(CASE type WHEN '数学' THEN score ELSE NULL END), 2) AS '数学',
ROUND(AVG(CASE type WHEN '英语' THEN score ELSE NULL END), 2) AS '英语',
'-' AS '总分'
FROM score
函数 AVG() 忽略 NULL 值,而不是将其作为 0 参与计算,也就是说 取平均值的时候 NULL 不参与计数